document.write( "Question 1010275: Prove (disprove) that there exists an A and B such that logA(B) = logB(A) where A ǂ B, both A and B > 0, and both A and B ǂ 1; note that a specific example is not a proof
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Algebra.Com's Answer #625760 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\"log%28A%2C%28B%29%29\"\"%22%22=%22%22\"\"log%28B%2C%28A%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Use the change of base formula, we have that the above
\n" ); document.write( "is true if and only if: \r
\n" ); document.write( "\n" ); document.write( "\"log%28A%2C%28B%29%29\"\"%22%22=%22%22\"\"1%2Flog%28A%2C%28B%29%29\"\r
\n" ); document.write( "\n" ); document.write( "which is true if and only if\r
\n" ); document.write( "\n" ); document.write( "\"%28log%28A%2C%28B%29%29%29%5E2\"\"%22%22=%22%22\"\"1%29\"\r
\n" ); document.write( "\n" ); document.write( "Use the principle of square roots, we have that the above
\n" ); document.write( "is true if and only if\r
\n" ); document.write( "\n" ); document.write( "\"log%28A%2C%28B%29%29\"\"%22%22=%22%22\"\"%22%22+%2B-+sqrt%281%29\"\r
\n" ); document.write( "\n" ); document.write( "By the definition of logarithms, that is equivalent to\r
\n" ); document.write( "\n" ); document.write( "\"A\"\"%22%22=%22%22\"\"B%5E%28%22%22+%2B-+1%29\"\r
\n" ); document.write( "\n" ); document.write( "We cannot use the + for that would make A = B, which is
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\n" ); document.write( "\n" ); document.write( "So the above is true if and only if \r
\n" ); document.write( "\n" ); document.write( "\"A\"\"%22%22=%22%22%22\"\"B%5E%28-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A\"\"%22%22=%22%22\"\"1%2FB\"\r
\n" ); document.write( "\n" ); document.write( "\"AB\"\"%22%22=%22%22\"\"1\"\r
\n" ); document.write( "\n" ); document.write( "and A ǂ B, both A and B > 0, and both A and B ǂ 1\r
\n" ); document.write( "\n" ); document.write( "Edwin
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