document.write( "Question 1010316: 2sin^2x-1=0\r
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Algebra.Com's Answer #625754 by lwsshak3(11628) $\"\"$ $\"About$

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2sin^2x-1=0
\n" ); document.write( "2(1-cos^2x)-1=0
\n" ); document.write( "2- 2cos^2x-1=0
\n" ); document.write( "-2cos^2x+1=0
\n" ); document.write( "1=2cos^2x
\n" ); document.write( "2cos^2x=1
\n" ); document.write( "cos^2x=1/2
\n" ); document.write( "cosx=ą√(1/2)=ą√2/2
\n" ); document.write( "x=45, 135, 225 and 315 deg (from 0 to 2pi)\r
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