document.write( "Question 1010296: can i have help with these two proofs?
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document.write( "1. X >Y
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document.write( "2. (Y v ~X) > (Y > Z) / ~Z > ~X \n" );
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Algebra.Com's Answer #625734 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! can i have help with these two proofs? \n" ); document.write( "1. X >Y \n" ); document.write( "2. (Y v ~X) > (Y > Z) / ~Z > ~X \n" ); document.write( " \r\n" ); document.write( "The conclusion is equivalent to ~~X > ~~Z by transposition\r\n" ); document.write( "which is equivalent to X > Y by double negation.\r\n" ); document.write( "We first form a conditional proof for X > Z:\r\n" ); document.write( "\r\n" ); document.write( "1. X > Y \r\n" ); document.write( "2. (Y v ~X) > (Y > Z) / X > Z\r\n" ); document.write( "\r\n" ); document.write( " |3. X ACP\r\n" ); document.write( " |4. Y 1,3 MP\r\n" ); document.write( " |5. Y v ~X 4 Add\r\n" ); document.write( " |6. Y > Z 2,5 MP\r\n" ); document.write( "7. X > Z 3-6, CP\r\n" ); document.write( "8. ~Z > ~X 7, Transposition\r\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 1. (A & U) < > ~R \r\n" ); document.write( " 2. ~(~R v ~A) / ~U\r\n" ); document.write( "\r\n" ); document.write( " 3. ~~R & ~~A 2, DM\r\n" ); document.write( " 4. R & A 3, DN\r\n" ); document.write( " 5. ~~R < > ~(A & U) 1, TR (transposition)\r\n" ); document.write( " 6. R <> ~(A & U) 5, DN\r\n" ); document.write( " 7. R 4, Simp.\r\n" ); document.write( " 8. ~(A & U) 6,7, MP\r\n" ); document.write( " 9. ~A v ~U 8, DM\r\n" ); document.write( "10. A 4, Simp.\r\n" ); document.write( "11. ~~A 10, DN\r\n" ); document.write( "12. ~U 9,11, DS (disjunctive syllogism)\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |