document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010262>Question 1010262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3 times the smaller of two numbers is increased by the larger, the result is 63. if five times the smaller is subtracted from twice the larger, the result is 16. find the numbers, please.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625710 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the bigger, x, and the smaller, y.<BR>\n" );
document.write( "Then we have<BR>\n" );
document.write( "3y + x = 63  and<BR>\n" );
document.write( "2x - 5y = 16<BR>\n" );
document.write( "Solve the first for x and substitute into the second...we get<BR>\n" );
document.write( "x = 63 - 3y<BR>\n" );
document.write( "and<BR>\n" );
document.write( "2(63 - 3y) - 5y = 16<BR>\n" );
document.write( "126 - 6y - 5y = 16<BR>\n" );
document.write( "-11y = -110<BR>\n" );
document.write( "y = 10<BR>\n" );
document.write( "x = 63 - 3(10) = 33 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );