document.write( "Question 1010264: Find the equation of the tangent line to the curve (x-y)^2=2x+1 at the point (4,1). \n" ); document.write( "
Algebra.Com's Answer #625709 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find the equation of the tangent line to the curve (x-y)^2=2x+1 at the point (4,1). \n" ); document.write( "-------------- \n" ); document.write( "(x-y)^2=2x+1 \n" ); document.write( "x^2 - 2xy + y^2 = 2x+1 \n" ); document.write( "Differentiate implicitly \n" ); document.write( "2xdx - 2ydx - 2xdy + 2ydy = 2dx \n" ); document.write( "xdx - ydx - xdy + ydy - dx = 0 \n" ); document.write( "(x-y-1)dx - (x - y)dy = 0 \n" ); document.write( "(x-y-1)dx = (x - y)dy \n" ); document.write( "dy/dx = (x-y-1)/(x-y) \n" ); document.write( "@ (4,1) dy/dx = 2/3 \n" ); document.write( "-------------------- \n" ); document.write( "y-1 = (2/3)(x-4)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |