document.write( "Question 1010264: Find the equation of the tangent line to the curve (x-y)^2=2x+1 at the point (4,1). \n" ); document.write( "
Algebra.Com's Answer #625709 by Alan3354(69443)\"\" \"About 
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Find the equation of the tangent line to the curve (x-y)^2=2x+1 at the point (4,1).
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\n" ); document.write( "(x-y)^2=2x+1
\n" ); document.write( "x^2 - 2xy + y^2 = 2x+1
\n" ); document.write( "Differentiate implicitly
\n" ); document.write( "2xdx - 2ydx - 2xdy + 2ydy = 2dx
\n" ); document.write( "xdx - ydx - xdy + ydy - dx = 0
\n" ); document.write( "(x-y-1)dx - (x - y)dy = 0
\n" ); document.write( "(x-y-1)dx = (x - y)dy
\n" ); document.write( "dy/dx = (x-y-1)/(x-y)
\n" ); document.write( "@ (4,1) dy/dx = 2/3
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\n" ); document.write( "y-1 = (2/3)(x-4)\r
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