document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010273>Question 1010273</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help! I've had trouble with this for a long time and always seem to be stuck on it. <BR>\n" );
document.write( "The length of a rectangle is three times the width of the rectangle. If the width of the rectangle is y units, what is the area of the rectangle?<BR>\n" );
document.write( "3y units2<BR>\n" );
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document.write( "3y2 units2\r<BR>\n" );
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document.write( "y + 3 units2\r<BR>\n" );
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document.write( "3y(y + 3) units2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625707 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes.  If the width is 10 and the length is three times that, you would say the length is 30.  If the width is 20, the length is 60.  Right?<BR>\n" );
document.write( "So, if the width is y units, the length is three times that too, or 3y units.<BR>\n" );
document.write( "Then the area is always length times width, and<BR>\n" );
document.write( "A = LW = (3y)(y) = 3y^2 square units </SPAN>\n" );
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