document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010230>Question 1010230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The voltage in a circuit is decaying according to the function V(t) = V0e^-0.48t, where V0 is the starting voltage, t is the time in seconds and V(t) is the voltage after t seconds. If the starting voltage is 6 volts, what will be the voltage after 2.6 seconds?<BR>\n" );
document.write( "Round your answer to the nearest hundredth of a volt </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625687 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Starting from<BR>\n" );
document.write( "V(t) = V0e^-0.48t<BR>\n" );
document.write( "we plug in to find<BR>\n" );
document.write( "V(2.6) = 6e^(-.48*2.6) = 1.72 volts </SPAN>\n" );
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