document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010229>Question 1010229</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ages of a parent and child add up to 30years. In 3years times, the parent will be 4 times as old as the child. Fine the current ages of the parent and the child. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625679 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages NOW, p and c.  Thus<BR>\n" );
document.write( "p + c = 30 so we have p = 30 - c<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "p + 3 = 4(c + 3)<BR>\n" );
document.write( "Substitute in and get<BR>\n" );
document.write( "30 - c + 3 = 4(c + 3)<BR>\n" );
document.write( "33 - c = 4c + 12<BR>\n" );
document.write( "21 = 5c<BR>\n" );
document.write( "c = 4.2 years<BR>\n" );
document.write( "p = 25.8 years </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );