document.write( "Question 1010222: How do I find the standard form of a circle?\r
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document.write( "The question states\r
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document.write( "x^2 + Y^2 +6x - 6y - 7 = 0 \n" );
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Algebra.Com's Answer #625677 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Let us complete the square twice, once in x and once in y and get \n" ); document.write( "x^2 + y^2 + 6x - 6y - 7 = 0 \n" ); document.write( "x^2 + 6x + 9 + y^2 - 6y + 9 - 7 = 0 + 9 + 9 \n" ); document.write( "(x + 3)^2 + (y - 3)^2 = 25 = 5^2 \n" ); document.write( "Center at (-3, 3) and radius 5. \n" ); document.write( " |