document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010219>Question 1010219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Distance it takes a car to stop varies directly as the square of the speed of the car. If it takes 125 feet for a car traveling 50 miles per hour to stop, what distance is required for a speed of 44 miles per hour?<BR>\n" );
document.write( "(round to the nearest hundredth if necessary) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625672 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625672\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We write this relationship as<BR>\n" );
document.write( "d = kv^2<BR>\n" );
document.write( "Now plugging in we get<BR>\n" );
document.write( "125 feet = k(55 mph)^2<BR>\n" );
document.write( "125 = 3025k<BR>\n" );
document.write( "k = .04132<BR>\n" );
document.write( "Then we find d using our new value of k...<BR>\n" );
document.write( "d = (.04132)(44^2) = 80 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );