document.write( "Question 86519This question is from textbook algebra structure and method
\n" ); document.write( ": I don't know how check to make sure the answer is right.
\n" ); document.write( "1500/45=2000/x
\n" ); document.write( "1500x=2000*45
\n" ); document.write( "1500x=90001500x/1500=90000/1500
\n" ); document.write( "x=90000/1500
\n" ); document.write( "x=60
\n" ); document.write( "I know the answer is correct but I need to check it now.
\n" ); document.write( "Could you tell me how to do that.
\n" ); document.write( "Thank you
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Algebra.Com's Answer #62567 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To check this, simply plug the solution back into the original equation\r
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\n" ); document.write( "\n" ); document.write( "\"1500%2F45=2000%2F60\" plug in \"x=60\"\r
\n" ); document.write( "\n" ); document.write( "Reduce the left side
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Solved by pluggable solver: Reducing Fractions Calculator
In order to reduce \"1500%2F45\", the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.
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\n" ); document.write( " In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of \"1500\" and \"45\" is \"\" (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by \"\"
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\n" ); document.write( " In other words, to reduce the fraction you do this
\n" ); document.write( " \"%28numerator%2FGCF%29%2F%28denominator%2FGCF%29=Reduced_Fraction\"
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\n" ); document.write( " \"%281500%2F%29%2F%2845%2F%29\" Plug in the numerator, denominator, and the GCF
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\n" ); document.write( " \"%28100%29%2F%2845%2F%29\" Now divide 1500 by to get 100. This is now the new numerator.
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\n" ); document.write( " \"100%2F3\" Now divide 45 by to get 3. This is now the new denominator.
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\n" ); document.write( " So
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\n" ); document.write( " \"%281500%2F%29%2F%2845%2F%29=100%2F3\"
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\n" ); document.write( " This means that \"1500%2F45\" reduces to \"100%2F3\"
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\n" ); document.write( " In other words, \"1500%2F45=100%2F3\"
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\n" ); document.write( "\n" ); document.write( "\"100%2F3=2000%2F60\"\r
\n" ); document.write( "\n" ); document.write( "Reduce the right side
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Solved by pluggable solver: Reducing Fractions Calculator
In order to reduce \"2000%2F60\", the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of \"2000\" and \"60\" is \"\" (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by \"\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " In other words, to reduce the fraction you do this
\n" ); document.write( " \"%28numerator%2FGCF%29%2F%28denominator%2FGCF%29=Reduced_Fraction\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"%282000%2F%29%2F%2860%2F%29\" Plug in the numerator, denominator, and the GCF
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\n" ); document.write( "
\n" ); document.write( " \"%28100%29%2F%2860%2F%29\" Now divide 2000 by to get 100. This is now the new numerator.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"100%2F3\" Now divide 60 by to get 3. This is now the new denominator.
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\n" ); document.write( " So
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\n" ); document.write( " \"%282000%2F%29%2F%2860%2F%29=100%2F3\"
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\n" ); document.write( " This means that \"2000%2F60\" reduces to \"100%2F3\"
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\n" ); document.write( " In other words, \"2000%2F60=100%2F3\"
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\n" ); document.write( "\n" ); document.write( "So now we're left with this\r
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\n" ); document.write( "\n" ); document.write( "\"100%2F3=100%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "which is true. So the answer is verified
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