document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010200>Question 1010200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need help with one more please:<BR>\n" );
document.write( "Differentiate as many times as necessary to evaluate f'''(-3) if f(x) = 2 ln( absolute value of x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625659 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=2ln|x|<BR>\n" );
document.write( "f'(x)=2/x or 2x^(-1)<BR>\n" );
document.write( "f''(x)=-2x(-2) or -2/x^2<BR>\n" );
document.write( "f'''(x)= 4x^(-3) or 4/x^3<BR>\n" );
document.write( "f'''(-3)= -4/27 </SPAN>\n" );
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