document.write( "Question 1010181: The sum of the digits of a three-digit number is 9. The tens digit is 3 times the hundreds digit. If the digits are reversed in order, the new number is 99 less than the original number. Find the original three-digit number. \n" ); document.write( "
Algebra.Com's Answer #625650 by josgarithmetic(39618)\"\" \"About 
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h, t, u for Hundred, Tens, Ones or Units.
\n" ); document.write( "Original Number, 100h+10t+u.\r
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\n" ); document.write( "\n" ); document.write( "\"system%28h%2Bt%2Bu=9%2Ct=3h%2C100u%2B10t%2Bh=-99%2B100h%2B10t%2Bu%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28h%2Bt%2Bu=9%2Ct=3h%2C99u-99h=-99%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28h%2Bt%2Bu=9%2Ct=3h%2C99h-99u=99%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28h%2B3h%2Bu=9%2Ch-u=1%29\"
\n" ); document.write( "Finish this.
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