document.write( "Question 1010181: The sum of the digits of a three-digit number is 9. The tens digit is 3 times the hundreds digit. If the digits are reversed in order, the new number is 99 less than the original number. Find the original three-digit number. \n" ); document.write( "
Algebra.Com's Answer #625650 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! h, t, u for Hundred, Tens, Ones or Units. \n" ); document.write( "Original Number, 100h+10t+u.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Finish this. \n" ); document.write( " |