document.write( "Question 1010182: Factor- 36x^2 - 81 . \n" ); document.write( "
Algebra.Com's Answer #625648 by Theo(13342)\"\" \"About 
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start with 36x^2 - 81 = y
\n" ); document.write( "set y = 0 to get 36x^2 - 81 = 0
\n" ); document.write( "add 81 to both sides of this equation to get 36x^2 = 81
\n" ); document.write( "divide both sides of this equation to get x^2 = 81/36
\n" ); document.write( "simplify to get x^2 = 2.25
\n" ); document.write( "take the square root of both sides of the equation to get x = 1.5 or x = -1.5\r
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\n" ); document.write( "\n" ); document.write( "this is also in the form of (a^2 - b^2) = (a + b) * (a - b)\r
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\n" ); document.write( "\n" ); document.write( "a^2 = 36x^2 so a = 6x
\n" ); document.write( "b^2 = 81 so b = 9\r
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\n" ); document.write( "\n" ); document.write( "you get (36x^2 - 81) = ((6x)^2 - 9^2) = (6x + 9) * (6x - 9)\r
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\n" ); document.write( "\n" ); document.write( "set each of these factors equal to 0 and you get 6x = -9 and 6x = 9\r
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\n" ); document.write( "\n" ); document.write( "solve for x in each to get x = -1.5 and x = 1.5\r
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\n" ); document.write( "\n" ); document.write( "you could also have used the quadratic formula which would have gotten you the same answer.\r
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\n" ); document.write( "\n" ); document.write( "the equation of 36x^2 - 81 = 0 yields:
\n" ); document.write( "a = 36
\n" ); document.write( "b = 0
\n" ); document.write( "c = -81\r
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\n" ); document.write( "\n" ); document.write( "the quadratic formula is x = (-b plus or minus sqrt(b^2-4ac)) divided by 2a.\r
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\n" ); document.write( "\n" ); document.write( "solve it and you will see that x = plus or minus 1.5.\r
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