document.write( "Question 1010026: Jill invested $2000, part at 12%/a and the remainder at 8%/a. At the end of one year the amount of interest from each investment were equal. How much was invested at each rate \n" ); document.write( "
Algebra.Com's Answer #625636 by Theo(13342)\"\" \"About 
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x = part invested at 12%.
\n" ); document.write( "y = part invested at 8%.\r
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\n" ); document.write( "\n" ); document.write( "interest on x = .12x
\n" ); document.write( "interest on y = .08y\r
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\n" ); document.write( "\n" ); document.write( "at the end of the year .12x = .08y\r
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\n" ); document.write( "\n" ); document.write( "x + y = 2000\r
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\n" ); document.write( "\n" ); document.write( "several ways to solve.
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\n" ); document.write( "\n" ); document.write( "from .12x = .08y, solve for y to get y = .12x/.08 = 1.5x\r
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\n" ); document.write( "\n" ); document.write( "in x + y = 2000, replace y with 1.5x to get x + 1.5x = 2000\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get 2.5x = 2000\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 2000 / 2.5 = 800.\r
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\n" ); document.write( "\n" ); document.write( "since x + y = 2000, y must be equal to 1200\r
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\n" ); document.write( "\n" ); document.write( ".12*800 = 96\r
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\n" ); document.write( "\n" ); document.write( ".08*1200 = 96\r
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\n" ); document.write( "\n" ); document.write( "the interest is equal so the solution is confirmed to be good.\r
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\n" ); document.write( "\n" ); document.write( "jill invested 800 at 12% and 1200 at 8%.\r
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