document.write( "Question 1010020: Following the function P(t)=1+ke^0.08t where k is a constant and t is the time in years. If the current population is 37,000 in how many years is the population expected to be 92,500? \n" ); document.write( "
Algebra.Com's Answer #625635 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"P%28t%29=1%2Bke%5E%280.08t%29+where+%7B%7B%7Bk\" is a constant and \"t\" is the time in years.
\n" ); document.write( "\"k=37000\"
\n" ); document.write( "\"P%28t%29=+92500\"\r
\n" ); document.write( "\n" ); document.write( "find: \"t\"\r
\n" ); document.write( "\n" ); document.write( "\"92500=1%2B37000e%5E%280.08t%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"92500-1=37000e%5E%280.08t%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"92499=37000e%5E%280.08t%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"92499%2F37000=e%5E%280.08t%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2.499972972972973=e%5E%280.08t%29\"........take a natural log of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"ln%282.499972972972973%29=ln%28e%5E%280.08t%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"ln%282.499972972972973%29=%280.08t%29ln%28e%29\"-----\"ln%28e%29=1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"ln%282.499972972972973%29=0.08t%0D%0A%0D%0A%0D%0A%7B%7B%7Bt=ln%282.499972972972973%29%2F0.08\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=0.9162799210049070%2F0.08\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=11.4534990125613375\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=11.5\"->\"t\"=\"11\"\"1%2F2\" years\r
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