document.write( "Question 1010113: Consider the function: f(x)=x²-8x+15
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Algebra.Com's Answer #625624 by MathTherapy(10552)\"\" \"About 
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Consider the function: f(x)=x²-8x+15
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\"f%28x%29+=+x%5E2+-+8x+%2B+15\"
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document.write( "a. \"f%28x%29+=+%28x+-+5%29%28x+-+3%29\"
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document.write( "   Zeroes, or \"highlight_green%28matrix%281%2C3%2Cx+=+5%2C+OR%2C+x+=+3%29%29\"\r
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document.write( "b. The x-coordinate of the vertex or the axis of symmetry is at: \"x+=+-b%2F%282a%29\", which in this case is: \"x+=+-+-+8%2F%282+%2A+1%29\", or \"x+=+8%2F2\", or \"highlight_green%284%29\"\r
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document.write( "c. You don't have to put it in vertex form to find the vertex, especially since the x-coordinate of the vertex is now known (\"x+=+4\"). All
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document.write( "   that's needed now is to substitute 4 for x into the equation, and the y-coordinate of the vertex will also be known, which by the way is: y = - 1.
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document.write( "   Vertex is therefore: (\"highlight_green%284%29\"\"%22%2C%22\"\"highlight_green%28-+1%29\")
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document.write( "However, since it's requested that you put the parabola in vertex form: \"f%28x%29+=+a%28x+-+h%29%5E2+%2B+k%29\", then by all means do so. \n" );
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