document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010137>Question 1010137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alice's Restaurant has a total of 258 seats. The number of seats in the non-smoking section is 51 more than twice the number of seats in the smoking section. How many seats are in each section? \r<BR>\n" );
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document.write( "I have tried to solve this by doing this equation: x+y=258<BR>\n" );
document.write( "                                                                            2x+51=258<BR>\n" );
document.write( "It seems that my equation does not work.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625606 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625606\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your first equation is correct, but your second equation is not correct.\r<BR>\n" );
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document.write( "Let<BR>\n" );
document.write( "x = number of seats in the non-smoking section<BR>\n" );
document.write( "y = number of seats in the smoking section\r<BR>\n" );
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document.write( "\"The number of seats in the non-smoking section is 51 more than twice the number of seats in the smoking section\"\r<BR>\n" );
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document.write( "means that\r<BR>\n" );
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document.write( "(number of non-smoking seats) = 2*(smoking seats) + 51\r<BR>\n" );
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document.write( "(x) = 2*(y) + 51\r<BR>\n" );
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document.write( "x = 2y + 51\r<BR>\n" );
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document.write( "So the second equation should be x = 2y+51. Note: if you made x the number of seats in the smoking section, then you'd have y = 2x+51. It's the same idea, just with the variables swapped. You'll get the same answers either way.\r<BR>\n" );
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document.write( "Go back to x+y = 258 and replace x with 2y+51\r<BR>\n" );
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document.write( "x+y = 258<BR>\n" );
document.write( "2y+51+y = 258\r<BR>\n" );
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document.write( "Now solve for y<BR>\n" );
document.write( "2y+51+y = 258<BR>\n" );
document.write( "3y+51 = 258<BR>\n" );
document.write( "3y+51-51 = 258-51<BR>\n" );
document.write( "3y = 207<BR>\n" );
document.write( "3y/3 = 207/3<BR>\n" );
document.write( "y = 69\r<BR>\n" );
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document.write( "Use this to find x<BR>\n" );
document.write( "x = 2y+51<BR>\n" );
document.write( "x = 2*69+51<BR>\n" );
document.write( "x = 138+51<BR>\n" );
document.write( "x = 189\r<BR>\n" );
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document.write( "There are 189 seats in the non-smoking section. There are 69 seats in the smoking section. </SPAN>\n" );
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