document.write( "Question 12334: find three consecutive odd integers such that the sum of the first three exceeds twice the fourth by 5. \n" ); document.write( "
Algebra.Com's Answer #6256 by bonster(299)\"\" \"About 
You can put this solution on YOUR website!
three consecutive odd integers
\n" ); document.write( "#1=x
\n" ); document.write( "#2=x+2
\n" ); document.write( "#3=x+4
\n" ); document.write( "#4=x+6\r
\n" ); document.write( "\n" ); document.write( "the sum of the first three exceeds twice the fourth by 5
\n" ); document.write( "keep in mind: if it says the sum exceeds another number by 5, add 5 to the sum
\n" ); document.write( "[x+(x+2)+(x+4)]+5=2(x+6)
\n" ); document.write( "3x+11=2x+12 <--subtract 2x from both sides
\n" ); document.write( "(3x+11)-2x=(2x+12)-2x
\n" ); document.write( "x+11=12 <--subtract 11 from both sides
\n" ); document.write( "(x+11)-11=12-11
\n" ); document.write( "x=1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if #1=x then #2 (x+2)=1+2=3, #3 (x+4)=1+4=5
\n" ); document.write( "your three numbers are 1, 3, 5 \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "the sum of the first three exceeds twice the fourth by 5
\n" ); document.write( "(1+3+5)+5=2(7)
\n" ); document.write( "4+10=14
\n" ); document.write( "14=14\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );