document.write( "Question 86487: I have a right triangle. a=2 and b=4 what does Cos(A)=?
\n" ); document.write( "I am having trouble with the problem. I know Cos(A)= b/c so i have to figure out what c= i believe? Thanks for the help.
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Algebra.Com's Answer #62559 by Edwin McCravy(20056)\"\" \"About 
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I have a right triangle. a=2 and b=4 what does Cos(A)=?
\n" ); document.write( "I am having trouble with the problem. I know Cos(A)= b/c so i have to figure out what c= i believe? Thanks for the help
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\n" ); document.write( "\n" ); document.write( "Yes, you have to calculate c using the Pythagorean theorem:\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2\" = \"a%5E2\" + \"b%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2\" = \"2%5E2\" + \"4%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2\" = 4 + 16\r
\n" ); document.write( "\n" ); document.write( "\"c%5E2\" = 20\r
\n" ); document.write( "\n" ); document.write( "c = \"sqrt%2820%29\"\r
\n" ); document.write( "\n" ); document.write( "c = \"sqrt%284%2A5%29\"\r
\n" ); document.write( "\n" ); document.write( "c = 2\"sqrt%285%29\"\r
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\n" ); document.write( "\n" ); document.write( "so cos(A) = \"b%2Fc\" = \"4%2F%282sqrt%285%29%29\" = \"2%2Fsqrt%285%29\" = \"%282%2Asqrt%285%29%29%2F%28sqrt%285%29sqrt%285%29%29\" = \"2sqrt%285%29%2F5\"
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