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You can put this solution on YOUR website!
sqrt(8x+49)-sqrt(2x+28)=3 Square both sides to get rid of sqrt
\n" ); document.write( "77+10x-2sqrt((2x+28)(8x+49))= 9
\n" ); document.write( "Subtract 10 x+77 from both sides:
\n" ); document.write( "-2sqrt((2x+28)(8x+49))= -68-10x
\n" ); document.write( "Raise both sides to the power of two:
\n" ); document.write( "4(2x+28)(8x+49)= (-68-10x)^2 On the left, FOIL
\n" ); document.write( "64x^2+1288x+5488= (-68-10x)^2 Square numbers on right (and remember that -10^2= -10*-10= 100, in other words, -*- = +)
\n" ); document.write( "64x^2+1288x+5488 = 100x^2+1360x+4624
\n" ); document.write( "Subtract 100x^2+1360x+4624 from both sides:
\n" ); document.write( "64x^2+1288x+5488 = 100x^2+1360x+4624
\n" ); document.write( "-
\n" ); document.write( "100x^2+1360x+4624= 100x^2+1360x+4624
\n" ); document.write( "------------------------------------
\n" ); document.write( "-36x^2-72x+864= 0 Let's factor the left side:
\n" ); document.write( "-36(x-4)(x+6)= 0 Now simplify by dividing both sides by -36 (and remember that 0 divided by any number = 0, so the right doesn't change)
\n" ); document.write( "(x-4)(x+6)= 0
\n" ); document.write( "x-4= 0 or x+6= 0
\n" ); document.write( "x= 4 or x= -6
\n" ); document.write( "Try each one of these in the equation to see which one makes the equation true. I've already done a lot of typing so you can do it on your own. You'll find that 4 is the correct answer. \n" ); document.write( "