document.write( "Question 1010093: Hi, I have worked out the following answers two these two questions but I am not sure if they are right? Help would be much appreciated.\r
\n" ); document.write( "\n" ); document.write( "1. Express Logx + 4Logy - (1/3)Logz as a single logarithm.\r
\n" ); document.write( "\n" ); document.write( "= Logx + Log(y)^4 - ³√z
\n" ); document.write( "= Logx (y^4)/(³√z) - Answer \r
\n" ); document.write( "\n" ); document.write( "Unsure if the answer should be = Log (xy^4)/(³√z) or the answer above, because in the question it does not specify a base. So I assume its of base 10 and apparently when it's of base 10 it can be written as Logx. Just unsure if its written with a large X next to the log or a small as displayed in the base of the Log?\r
\n" ); document.write( "\n" ); document.write( "2. Express Log (Base 3) (9a³/√b) in terms of simple logarithms.\r
\n" ); document.write( "\n" ); document.write( "= Log (Base 3)9 + Log (Base 3)a³ - Log (Base 3)√b
\n" ); document.write( "= Log (Base 3)9 + 3Log (Base 3)a - 1/2Log (Base 3)b Answer\r
\n" ); document.write( "\n" ); document.write( "Unsure if the answer should be
\n" ); document.write( "= 9Log (Base 3) + 3Log (Base 3)a - 1/2Log (Base 3)b ?
\n" ); document.write( "

Algebra.Com's Answer #625557 by josgarithmetic(39628)\"\" \"About 
You can put this solution on YOUR website!
Logx + 4Logy - (1/3)Logz\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28log%28%28%28xy%5E4%29%2F%28z%5E%281%2F3%29%29%29%29%29\"
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