document.write( "Question 86477: Area of a painting. A rectangular painting with a width of x centimeters has an area of x^2+50x square centimeters. Find a binomial that represents the length. \n" ); document.write( "
Algebra.Com's Answer #62552 by chitra(359)\"\" \"About 
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To find the lenght of the rectangle given its area and its width. \r
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\n" ); document.write( "\n" ); document.write( "Area = \"x%5E2+%2B+50x\" \r
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\n" ); document.write( "\n" ); document.write( "width = x units.\r
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\n" ); document.write( "\n" ); document.write( "To find the lenght.. ?? \r
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\n" ); document.write( "\n" ); document.write( "Area = length * width \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+50x+\" = length * x\r
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\n" ); document.write( "\n" ); document.write( "x(x + 50) = length * x \r
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\n" ); document.write( "\n" ); document.write( "==> (x + 50) = length \r
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\n" ); document.write( "\n" ); document.write( "Hence, the length of the rectangular painting is (50 + x) units.\r
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\n" ); document.write( "\n" ); document.write( "Thus, the solution\r
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