document.write( "Question 86478: factor completely\r
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Algebra.Com's Answer #62551 by chitra(359)\"\" \"About 
You can put this solution on YOUR website!
The given expression is: \r
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\n" ); document.write( "\n" ); document.write( "\"+-3t+%2B+3t%5E2+-+6t+\" \r
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\n" ); document.write( "\n" ); document.write( "Here, we observe that there are two temrs which contain t and one term that contain \"t%5E2\". So grouping like terms, we get: \r
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\n" ); document.write( "\n" ); document.write( "\"3t%5E2+-+9t\" \r
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\n" ); document.write( "\n" ); document.write( "Here 3t can be taken out as the common factor. Hence, this cna be factored as: \r
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\n" ); document.write( "\n" ); document.write( "3t(t - 3) \r
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\n" ); document.write( "\n" ); document.write( "NOTE: If the given quadratic is equated top zero then the value of t can be found out in the way as shown below. \r
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\n" ); document.write( "\n" ); document.write( "3t^2 - 9t = 0 \r
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\n" ); document.write( "\n" ); document.write( "==> 3t(t - 3) = 0 \r
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\n" ); document.write( "\n" ); document.write( "==> 3t = 0 OR t - 3 = 0 \r
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\n" ); document.write( "\n" ); document.write( "==> t = 0 OR t = 3\r
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\n" ); document.write( "\n" ); document.write( "Hence, the solution..\r
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