document.write( "Question 1010001: Find the coordinates of the point that is equidistant from (-2,5), (8,5), and (6,7). \n" ); document.write( "
Algebra.Com's Answer #625487 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Find the coordinates of the point that is equidistant from \n" ); document.write( "(-2,5), (8,5), and (6,7). \n" ); document.write( "----- \n" ); document.write( "From (-2,5)::sqrt[(x+2)^2+(y-5)^2] \n" ); document.write( "From (8,5):: sqrt[(x-8)^2+(y-5)^2] \n" ); document.write( "From (6,7):: sqrt[(x-6)^2+(y-7)^2] \n" ); document.write( "------ \n" ); document.write( "Equate rows 1 and 2:: \n" ); document.write( "(x+2)^2 = (x-8)^2 \n" ); document.write( "x^2 + 4x + 4 = x^2 - 16x + 64 \n" ); document.write( "----- \n" ); document.write( "4x + 4 = -16x + 64 \n" ); document.write( "20x = 60 \n" ); document.write( "x = 3 \n" ); document.write( "---- \n" ); document.write( "Solve for \"y\":: \n" ); document.write( "Equate rows 2 and 3 \n" ); document.write( "----- \n" ); document.write( "(x-8)^2 + (y-5)^2 = (x-6)^2 + (y-7)^2 \n" ); document.write( "---- \n" ); document.write( "Since x = 3:: \n" ); document.write( "5^2 + y^2 - 10y + 25 = 3^2 + y^2 - 14y + 49 \n" ); document.write( "------ \n" ); document.write( "4y + 50 = 58 \n" ); document.write( "--- \n" ); document.write( "4y = 8 \n" ); document.write( "y = 2 \n" ); document.write( "---- \n" ); document.write( "Ans: (3,2) \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------- \n" ); document.write( " |