document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1010002>Question 1010002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two values of k such that the points (-3,4), (0,k), and (k,10) are collinear. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625484 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find two values of k such that the points (-3,4), (0,k), and (k,10) are collinear. <BR>\n" );
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document.write( "Look at the slopes::<BR>\n" );
document.write( "1st point to 3rd point::<BR>\n" );
document.write( "(k-4)/(0+3) = (10-4)/(k+3)<BR>\n" );
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document.write( "Cross multiply::<BR>\n" );
document.write( "k^2 - k - 12 = 3*6<BR>\n" );
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document.write( "k^2 - k - 30 = 0<BR>\n" );
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document.write( "(k-6)(k+5) = 0<BR>\n" );
document.write( "k = 6 or k = -5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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