document.write( "Question 1009964: 1-Find an equation of the tangent line to the graph of f(x)=(x^3+1)/(x^2+x+1)
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\n" ); document.write( "\n" ); document.write( "2-Find the equation of the tangent line to the curve at the point (4,1).
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Algebra.Com's Answer #625445 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
The slope in general would be \r
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\n" ); document.write( "\n" ); document.write( "\"m=%28x%5E4%2B2x%5E3%2B3x%5E2-2x-1%29%2F%28x%5E2%2Bx%2B1%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "For the point whose x coordinate is 1,
\n" ); document.write( "\"f%281%29=y=%281%5E3%2B1%29%2F%281%5E2%2B1%2B1%29\"
\n" ); document.write( "\"f%281%29=y=2%2F4=1%2F2\"
\n" ); document.write( "the point being (1, 1/2).\r
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\n" ); document.write( "\n" ); document.write( "The slope for x=1, according to the formula found for \"m=df%2Fdx\",
\n" ); document.write( "is \"%281%5E3%2B2%2A1%5E3%2B3%2A1%5E2-2%2A1-1%29%2F%282%5E2%29\"
\n" ); document.write( "\"3%2F4\",\r
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\n" ); document.write( "\n" ); document.write( "Then if using point-slope linear equation form,
\n" ); document.write( "\"highlight%28y-1%2F2=%283%2F4%29%28x-1%29%29\"
\n" ); document.write( "or put into slope-intercept form,
\n" ); document.write( "\"y=%283%2F4%29x-3%2F4%2B1%2F2\"
\n" ); document.write( "\"y=%283%2F4%29x-3%2F4%2B2%2F4\"
\n" ); document.write( "\"highlight%28y=%283%2F4%29x-1%2F4%29\"\r
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\n" ); document.write( "\n" ); document.write( "The other question can then be handled much the same, just re-using the formula for the slope and the given point.\r
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\n" ); document.write( "The mnemonic for formula of derivative of a rational function goes as \"%28ho%2Adhi-hi%2Adho%29%2F%28ho%2Aho%29\" .
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