document.write( "Question 1009924: Solve the following inequality using interval notation \r
\n" ); document.write( "\n" ); document.write( "1/x+3 + 1/x is greater than or equal to 0 \r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP
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Algebra.Com's Answer #625383 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Put over a common denominator
\n" ); document.write( "(x+x+3)/x(x+3)>=0
\n" ); document.write( "(2x+3)/x(x+3)>=0
\n" ); document.write( "Critical values are
\n" ); document.write( "0, -3, and -3/2;
\n" ); document.write( "When x <-3, say -4, the numerator is negative and the denominator positive, so it doesn't work.
\n" ); document.write( "when x is -2, both are positive and it does work
\n" ); document.write( "When x=-3/2, which is allowed, the value is 0.
\n" ); document.write( "When x is -1, it is +/-+, which doesn't work.
\n" ); document.write( "When x is >0 it does work.
\n" ); document.write( "(-3,-3/2] U [0,oo)
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%281%2F%28x%2B3%29%29%2B%281%2Fx%29%29\"
\n" ); document.write( "Note where the graph is positive
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