document.write( "Question 1009924: Solve the following inequality using interval notation \r
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document.write( "1/x+3 + 1/x is greater than or equal to 0 \r
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document.write( "PLEASE HELP \n" );
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Algebra.Com's Answer #625383 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Put over a common denominator \n" ); document.write( "(x+x+3)/x(x+3)>=0 \n" ); document.write( "(2x+3)/x(x+3)>=0 \n" ); document.write( "Critical values are \n" ); document.write( "0, -3, and -3/2; \n" ); document.write( "When x <-3, say -4, the numerator is negative and the denominator positive, so it doesn't work. \n" ); document.write( "when x is -2, both are positive and it does work \n" ); document.write( "When x=-3/2, which is allowed, the value is 0. \n" ); document.write( "When x is -1, it is +/-+, which doesn't work. \n" ); document.write( "When x is >0 it does work. \n" ); document.write( "(-3,-3/2] U [0,oo) \n" ); document.write( " \n" ); document.write( "Note where the graph is positive \n" ); document.write( " |