document.write( "Question 1009912: Write an exponential function such that f(-2) = 25 and f(1) = 8/5.
\n" ); document.write( "I got F(x) = 6.25*(0.4) ͯ but my teacher tells me its not 6.25 but 4. Where do I get the 4 from? \r
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Algebra.Com's Answer #625378 by MathLover1(20850)\"\" \"About 
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\"f%28x%29=ab%5Ex\" can be the form of the exponential function.
\n" ); document.write( "Two points are (\"-2\",\"25\") and (\"1\", \"8%2F5\").\r
\n" ); document.write( "\n" ); document.write( "\"25=ab%5E%28-2%29\"
\n" ); document.write( "\"1=ab%5E%288%2F5%29\"\r
\n" ); document.write( "\n" ); document.write( "solve the system:\r
\n" ); document.write( "\n" ); document.write( "Take logarithms of both sides, base of your choice, and you will have a linear equation. You would need to make an adjustment to the vertical axis component of your given points.\r
\n" ); document.write( "\n" ); document.write( "\"log%2825%29=log%28ab%5E%28-2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%285%5E2%29=log%28a%29%2Blog%28b%5E%28-2%29%29\"
\n" ); document.write( "\"2log%285%29=log%28a%29%2B%28-2%29log%28b%29\"
\n" ); document.write( "\"2log%285%29=log%28a%29-2log%28b%29\".......eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"log%281%29=log%28ab%5E%288%2F5%29%29\"
\n" ); document.write( "\"0=log%28a%29%2Blog%28b%5E%288%2F5%29%29\"
\n" ); document.write( "\"0=log%28a%29%2B%288%2F5%29log%28b%29\".......eq.2\r
\n" ); document.write( "\n" ); document.write( "subtract eq.1 from eq.2\r
\n" ); document.write( "\n" ); document.write( "\"0-2log%285%29=log%28a%29-log%28a%29%2B%288%2F5%29log%28b%29%2B2log%28b%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-2log%285%29=%288%2F5%29log%28b%29%2B%2810%2F5%29log%28b%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-2log%285%29=%2818%2F5%29log%28b%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%285%5E-2%29=log%28b%5E%2818%2F5%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"5%5E-2=b%5E%2818%2F5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"b+=+1%2F5%5E%285%2F9%29\"\r
\n" ); document.write( "\n" ); document.write( "\"b+=+0.4\"\r
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\n" ); document.write( "\n" ); document.write( "now find \"a\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28a%29=-%288%2F5%29log%28b%29\" from eq.2\r
\n" ); document.write( "\n" ); document.write( "\"log%28a%29=-%288%2F5%29log%280.4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28a%29=log%280.4%5E%28-%288%2F5%29%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=0.4%5E%28-%288%2F5%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=1%2F%280.4%5E%288%2F5%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a=1%2F0.230832\"\r
\n" ); document.write( "\n" ); document.write( "\"a=4.3321549871\"\r
\n" ); document.write( "\n" ); document.write( "\"a=4\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"f%28x%29=4%280.4%29%5Ex\"
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