document.write( "Question 1009896: The perimeter of a rectangle is 76 cm. if the width is doubled and the length is halved, the new rectangle has a perimeter of 62 cm. What are the dimensions of the original rectangle and what is the area of the new rectangle? \n" ); document.write( "
Algebra.Com's Answer #625366 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The formula for perimeter is:
\n" ); document.write( "(1) \"+76+=+2L+%2B+2W+\"
\n" ); document.write( "Also given:
\n" ); document.write( "(2) \"+62+=+2%2A%28L%2F2%29+%2B+2%2A%28+2W+%29+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "(2) \"+62+=+L+%2B+4W+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+76+=+2L+%2B+2W+\"
\n" ); document.write( "(1) \"+38+=+L+%2B+W+\"
\n" ); document.write( "-------------------
\n" ); document.write( "Subtract (1) from (2)
\n" ); document.write( "(2) \"+62+=+L+%2B+4W+\"
\n" ); document.write( "(1) \"+-38+=+-L+-+W+\"
\n" ); document.write( "--------------------
\n" ); document.write( "\"+24+=+3W+\"
\n" ); document.write( "\"+W+=+8+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+38+=+L+%2B+W+\"
\n" ); document.write( "(1) \"+38+=+L+%2B+8+\"
\n" ); document.write( "(1) \"+L+=+30+\"
\n" ); document.write( "The dimensions of the original rectangle are:
\n" ); document.write( "8 x 30
\n" ); document.write( "------------------
\n" ); document.write( "The area of the new rectangle is:
\n" ); document.write( "\"+A+=+%28+L%2F2+%29%2A%28+2W+%29+\"
\n" ); document.write( "\"+A+=+15%2A16+\"
\n" ); document.write( "\"+A+=+240+\"
\n" ); document.write( "240 cm2
\n" ); document.write( "
\n" );