document.write( "Question 1009849: If 3cosx-4sinx=5,then 3sinx+4cosx=? \n" ); document.write( "
Algebra.Com's Answer #625348 by ikleyn(52855)\"\" \"About 
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\n" ); document.write( "If 3cosx - 4sinx = 5, then 3sinx + 4cosx =?
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document.write( "3*cosx - 4*sinx = 5.            (1)\r\n" );
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document.write( "Let us rewrite this equation in the form\r\n" );
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document.write( "\"3%2F5\".cos(x) - \"4%2F5\".sin(x) = 1.     (2)\r\n" );
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document.write( "Now consider the right-angled triangle with the sides (3,4,5), and let \"alpha\" be its smallest of two acute angles.\r\n" );
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document.write( "Then \"sin%28alpha%29\" = \"3%2F5\" and \"cos%28alpha%29\" = \"4%2F5\",\r\n" );
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document.write( "so we can rewrite the left side of the equation (2) in the form \r\n" );
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document.write( "\"sin%28alpha%29%2Acos%28x%29+-+cos%28alpha%29%2Asin%28x%29\" = 1,   or\r\n" );
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document.write( "\"sin%28alpha+-+x%29\" = 1.\r\n" );
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document.write( "It implies that \r\n" );
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document.write( "\"alpha+-+x\" = \"pi%2F2\"   and\r\n" );
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document.write( "\"cos%28alpha+-+x%29\" = 0.                  (3)\r\n" );
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document.write( "But, from the other side, \r\n" );
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document.write( "\"cos%28alpha-x%29\" = \"cos%28alpha%29%2Acos%28x%29\" + \"sin%28alpha%29%2Asin%28x%29\".\r\n" );
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document.write( "Now substitute here \"cos%28alpha%29\" = \"4%2F5\" and \"sin%28alpha%29\" = \"3%2F5\", and you will get\r\n" );
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document.write( "\"%284%2F5%29%2Acos%28x%29\" + \"%283%2F5%29%2Asin%28x%29\" = \"0\".   (4)\r\n" );
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document.write( "As a last step, multiply both sides of (4) by 5, and you will get\r\n" );
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document.write( "4*cos(x) + 3*sin(x) = 0.\r\n" );
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document.write( "The problem is solved.\r\n" );
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document.write( "Answer.  If 3cosx - 4sinx = 5, then 3sinx + 4cosx = 0.\r\n" );
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