document.write( "Question 1009854: Identify the variables, write a system of equations to solve
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\n" ); document.write( "When she rows with the current, Mindy can row 24 miles in 3 hours. Against the same current, Mindy can row only ⅔ of this distance in 4 hours. Find the rate of the current and Mindy's rowing rate in still water. Assume that both are constant.
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Algebra.Com's Answer #625337 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
rate * time = distance
\n" ); document.write( "let a = the rate of the boat
\n" ); document.write( "let b = the rate of the current.\r
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\n" ); document.write( "\n" ); document.write( "with the current, the rates are additive.
\n" ); document.write( "against the current, the rate are subtactive.\r
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\n" ); document.write( "\n" ); document.write( "going with the current, rate * time becomes:\r
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\n" ); document.write( "\n" ); document.write( "(a + b) * 3 = 24\r
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\n" ); document.write( "\n" ); document.write( "going agains the current, rate * time becomes:\r
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\n" ); document.write( "\n" ); document.write( "(a - b) * 4 = 16\r
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\n" ); document.write( "\n" ); document.write( "simplify these equations to get:\r
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\n" ); document.write( "\n" ); document.write( "3a + 3b = 24
\n" ); document.write( "4a - 4b = 16\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by 4 and multiply the second equation by 3 to get:\r
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\n" ); document.write( "\n" ); document.write( "12a + 12b = 96
\n" ); document.write( "12a - 12b = 48\r
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\n" ); document.write( "\n" ); document.write( "add the equations together to get:\r
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\n" ); document.write( "\n" ); document.write( "24a = 144\r
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\n" ); document.write( "\n" ); document.write( "solve for a to get a = 6\r
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\n" ); document.write( "\n" ); document.write( "your original equations are:\r
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\n" ); document.write( "\n" ); document.write( "(a + b) * 3 = 24
\n" ); document.write( "(a - b) * 4 = 16\r
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\n" ); document.write( "\n" ); document.write( "replace a in the first equation to get:\r
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\n" ); document.write( "\n" ); document.write( "(6 + b) * 3 = 24
\n" ); document.write( "distribute the multiplication to get:
\n" ); document.write( "18 + 3b = 24
\n" ); document.write( "subtract 18 from both sides to get:
\n" ); document.write( "3b = 6
\n" ); document.write( "solve for b to get:
\n" ); document.write( "b = 2\r
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\n" ); document.write( "\n" ); document.write( "you have a = 6 and b = 2
\n" ); document.write( "this means the rate of the boat is 6 mph and the rate of the current is 2 mph.\r
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\n" ); document.write( "\n" ); document.write( "go back to your original equations again and replace a with 6 and b with 2 to get:\r
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\n" ); document.write( "\n" ); document.write( "(a + b) * 3 = 24 becomes (6+2) * 3 = 24 which becomes 8*3 = 24 which becomes 24 = 24.\r
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\n" ); document.write( "\n" ); document.write( "(a - b) * 4 = 16 becomes (6-2) * 4 = 16 which becomes 4 * 4 = 16 which becomes 16 = 16.\r
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\n" ); document.write( "\n" ); document.write( "this confirms the solutions are correct.\r
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\n" ); document.write( "\n" ); document.write( "the rate of the boat is 6 miles per hour.
\n" ); document.write( "the rate of the current is 2 miles per hour.\r
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