document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009837>Question 1009837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Be glad if someone could help me with this. Thanks\r<BR>\n" );
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document.write( "If an={-3,2,7,12,17...}\r<BR>\n" );
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document.write( "Determine the sum of the firts 40 terms of an </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625318 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is an arithmetic sequence<BR>\n" );
document.write( "the summation of the first n terms = (n/2)(2a + d(n-1)) where a is the first term and d is the difference between terms<BR>\n" );
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document.write( "In our problem, n = 40, d = 5 and a = -3<BR>\n" );
document.write( "summation of first 40 terms = (40/2)(2*(-3) + 5(40-1)) = 3780<BR>\n" );
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