document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009828>Question 1009828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If log(3x-1)-log2=3, what is the value of x<BR>\n" );
document.write( "THANK YOU </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625312 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> start with:\r<BR>\n" );
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document.write( "log(3x-1) - log(2) = 3\r<BR>\n" );
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document.write( "since log(a) - log(b) = log(a/b), the equation becomes:\r<BR>\n" );
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document.write( "log((3x-1)/2) = 3\r<BR>\n" );
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document.write( "this is true if and only if 10^3 = (3x-1)/2\r<BR>\n" );
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document.write( "since 10^3 = 1000, then:\r<BR>\n" );
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document.write( "1000 = (3x-1)/2\r<BR>\n" );
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document.write( "multiply both sides of this equation by 2 to get:\r<BR>\n" );
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document.write( "3x-1 = 2000\r<BR>\n" );
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document.write( "add 1 to both sides of the equation to get:\r<BR>\n" );
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document.write( "3x = 2001\r<BR>\n" );
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document.write( "divide both sides of the equation by 3 to get:\r<BR>\n" );
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document.write( "x = 667\r<BR>\n" );
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document.write( "that's your solution.\r<BR>\n" );
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document.write( "when x = 667, log(3x-1) - log(2) = 3 becomes log(3*667-1) - log(2) = 3 which becomes 3 = 3.\r<BR>\n" );
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document.write( "this confirms the solution is correct.\r<BR>\n" );
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document.write( "your solution is that x = 667.\r<BR>\n" );
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