document.write( "Question 86443: It took 6 hours to travel to town, and it took up to 8 hours to travel back, becasue your return trip speed was 10mph less than the outgoing speed. What was your return trip speed?\r
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Algebra.Com's Answer #62531 by scianci(186)\"\" \"About 
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distance out = distance back
\n" ); document.write( "(rate)(time) out = (rate)(time) back
\n" ); document.write( "the respective times are given as 6 and 8
\n" ); document.write( "the rate out is 10 + the rate back
\n" ); document.write( "use a variable to represent the rate back
\n" ); document.write( "plug in the resulting expressions for rate out and rate back
\n" ); document.write( "plug in 6 and 8 for the times
\n" ); document.write( "solve the resulting equation for the variable
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