document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009783>Question 1009783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jeremy has a collection of dimes and quarters. Overall, he has 51 coins and their total value is $10.35. What is the total value of ONLY the quarters? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625285 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d+q= 51 subtract d fom both sides<BR>\n" );
document.write( "q= 51-d we'll use this value for q in the next equation<BR>\n" );
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document.write( "0.10d+0.25q= 10.35 substitute for q<BR>\n" );
document.write( "0.10d+0.25(51-d)= 10.35<BR>\n" );
document.write( "0.10d+12.75-0.25d= 10.35 Add q on left and subtract 12.75 on both sides<BR>\n" );
document.write( "-0.15d= -2.4 <BR>\n" );
document.write( "d= -2.4/-0.15 (remember that -/-= +)<BR>\n" );
document.write( "d= 16 Jeremy has 16 dimes<BR>\n" );
document.write( "51-16= 35 Jeremy has 35 quarters<BR>\n" );
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document.write( "16(0.10)= 1.60<BR>\n" );
document.write( "35(0.25)= 8.75<BR>\n" );
document.write( "_ _ _ _ _ -------<BR>\n" );
document.write( "Total: ... 10.35 We have the correct answer </SPAN>\n" );
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