document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009788>Question 1009788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have 2.5 kg 5% solution. How much 20% solution should be mixed to it to get a 12 % concentrated solution ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625270 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount of 20% solution you are adding, x.  The set up is like this<BR>\n" );
document.write( ".05(2.5) + .20x = .12(2.5 + x)<BR>\n" );
document.write( ".125 + .2x = .3 + .12x<BR>\n" );
document.write( ".08x = .175<BR>\n" );
document.write( "x = .175/.08 = 2 3/16 kg or 2.1875 kg of 20% solution </SPAN>\n" );
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