document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009726>Question 1009726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle exceeds its width by 5m.  If the width is increased by 1m and the length is decreased by 2m, the area of the new rectangle is 4 sq m less than the area of the original rectangle.  Find the dimensions of the original rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625242 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area is A = LW for a rectangle.<BR>\n" );
document.write( "We have originally<BR>\n" );
document.write( "L = W + 5<BR>\n" );
document.write( "Then the area is (W+5)W = W^2 + 5W<BR>\n" );
document.write( "Then<BR>\n" );
document.write( "(L-2)(W+1) = W^2 + 5W - 4<BR>\n" );
document.write( "Substituting we get<BR>\n" );
document.write( "(W+5 - 2)(W+1) = W^2 + 5W - 4<BR>\n" );
document.write( "(W + 3)(W + 1) = W^2 + 5W - 4<BR>\n" );
document.write( "W^2 + 4W + 3 = W^2 + 5W - 4<BR>\n" );
document.write( "and W = 7 m so that<BR>\n" );
document.write( "L = 12 m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );