document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86436>Question 86436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 6 ft longer than its width. The perimeter is 84 ft . What is the length?\r<BR>\n" );
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document.write( "84=2w+2l then I forget how to do this. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62524 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62524\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That's a good start:<BR>\n" );
document.write( "2W + 2L = 84 But...L = W+6, so substitute this for L.<BR>\n" );
document.write( "2W + 2(W+6) = 84 Simplify and solve for W.<BR>\n" );
document.write( "2W + 2W + 12 = 84 Combine like-terms.<BR>\n" );
document.write( "4W + 12 = 84 Subtract 12 from both sides.<BR>\n" );
document.write( "4W = 72 Divide both sides by 4.<BR>\n" );
document.write( "W = 18<BR>\n" );
document.write( "The width is 18 ft.<BR>\n" );
document.write( "The length, L = W+6 = 18+6 = 24 ft.<BR>\n" );
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