document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009759>Question 1009759</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A dealer wishes to obtain 80 pounds of mixed cookies to sell for one dollar per pound. If he mixes cookies worth $1.20 per pound with the cookies worth $.70 per pound, find the number of pounds of each kind he should use </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625235 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the amount at $1.20, x.<BR>\n" );
document.write( "Then the amount at $.70 would be 80-x.<BR>\n" );
document.write( "The set up is then<BR>\n" );
document.write( "1.20x + .70(80-x) = 1(80)<BR>\n" );
document.write( "1.2x + 56 - .7x = 80<BR>\n" );
document.write( ".5x = 24<BR>\n" );
document.write( "x = 48 pounds of the  $1.20<BR>\n" );
document.write( "80-x = 32 pounds of the $.70 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );