document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009749>Question 1009749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the larger of two numbers is 1 less than 3 times the smaller number. If twice the smaller number is increased by the larger number, the result is 18 more than the larger number. find both numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625234 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the larger x and the smaller number y.  Then we have<BR>\n" );
document.write( "x = 3y - 1<BR>\n" );
document.write( "and<BR>\n" );
document.write( "2y + x = 18 + x<BR>\n" );
document.write( "from which we get<BR>\n" );
document.write( "2y = 18<BR>\n" );
document.write( "y = 9<BR>\n" );
document.write( "Plugging that in above we get<BR>\n" );
document.write( "x = 3(9) - 1 = 26 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );