document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009703>Question 1009703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the average of 7 distinct odd numbers is 39, the smallest number is 31 and the largest number is 53, what is the number in the middle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625213 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The total is 7*39=273.<BR>\n" );
document.write( "Two numbers are known, 31 and 53, and they make 84.<BR>\n" );
document.write( "The other 5 must add up to 273-84= 189.<BR>\n" );
document.write( "The smallest is 33, the largest 51.<BR>\n" );
document.write( "The average value is 37.8<BR>\n" );
document.write( "At least 3 numbers have to be below that, and they would be 33,35,37, whose sum is 105.<BR>\n" );
document.write( "That leaves 84 for the other two, and they are 41 and 43.\r<BR>\n" );
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document.write( "The list of numbers is <BR>\n" );
document.write( "31,33,35,37,41,43,53.  They average to 39, and the number in the middle is 37. </SPAN>\n" );
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