document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009728>Question 1009728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/x+3 + 1/x >_ 0 \r<BR>\n" );
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document.write( "PLEASE HELP  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625206 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two critical points are -3 and 0.<BR>\n" );
document.write( "Set 1/(x+3)>=(-1/x)<BR>\n" );
document.write( "x>=-x-3<BR>\n" );
document.write( "2x>=-3<BR>\n" );
document.write( "x>=-3/2.  that is another key point.\r<BR>\n" );
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document.write( "x<-3, pick -4<BR>\n" );
document.write( "(-1)+(-1/4) not >=0, so not in interval<BR>\n" );
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document.write( "pick -2<BR>\n" );
document.write( "1-1/2 is >=0<BR>\n" );
document.write( "-3/2 works (2/3)-(2/3)=0<BR>\n" );
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document.write( "between -3/2 and 0, however, it does not work.<BR>\n" );
document.write( "x=-1<BR>\n" );
document.write( "1/2-(1)=-1/2.<BR>\n" );
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document.write( "When x >=0, then it works, since both are positive,<BR>\n" );
document.write( "(-oo,-3) does not work<BR>\n" );
document.write( "(-3,-1.5} works<BR>\n" );
document.write( "[0,oo) works<BR>\n" );
document.write( "(-3,-1.5] U [0,oo)\r<BR>\n" );
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