document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009704>Question 1009704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 38 when 8 is added to twice one of the numbers the result is five times the other numbers.find the two numbers.thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625146 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "F=first number; S=second number<BR>\n" );
document.write( ".<BR>\n" );
document.write( "F+S=38<BR>\n" );
document.write( "S=38-F . Use this to substitute for S below.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2F+8=5S . Substitute for S from above.<BR>\n" );
document.write( "2F+8=5(38-F)<BR>\n" );
document.write( "2F+8=190-5F<BR>\n" );
document.write( "7F=182<BR>\n" );
document.write( "F=26<BR>\n" );
document.write( "ANSWER 1: The first number is 26.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "S=38-F=38-26=12<BR>\n" );
document.write( "ANSWER 2: The second number is 12.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
document.write( "2F+8=5S<BR>\n" );
document.write( "2(26)+8=5(12)<BR>\n" );
document.write( "52+8=60<BR>\n" );
document.write( "60=60\r<BR>\n" );
document.write( "<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );