document.write( "Question 1009655: 2x-3y=16 where x=3y+11 Have tried 2x-3y+3y+11=16 2x+11-11=16-11 2x=5 but answer cannot be fraction what am I doing wrong here should I solve the problem 2x-3y=16 first then answer would be = -3\r
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Algebra.Com's Answer #625124 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "You must learn to substitute:\r\n" );
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document.write( "                2x-3y=16 where x=3y+11 \r\n" );
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document.write( "Replace the x in the first equation by what x equals in the\r\n" );
document.write( "second equation, 3y+11, placed in parentheses (3y+11):\r\n" );
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document.write( "          2(3y+11)-3y=16   \r\n" );
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document.write( "Distribute to remove the parentheses\r\n" );
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document.write( "             6y+22-3y=16  \r\n" );
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document.write( "Combine the two like terms on the left 6y and -3y, getting 3y\r\n" );
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document.write( "                3y+22=16\r\n" );
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document.write( "Add -22 to both sides\r\n" );
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document.write( "                3y+22=16\r\n" );
document.write( "                  -22=-22\r\n" );
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document.write( "                3y   =-6\r\n" );
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document.write( "Divide both sides by 3\r\n" );
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document.write( "Now substitute (2) for y in \r\n" );
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document.write( "                x=3y+11\r\n" );
document.write( "                x=3(-2)+11\r\n" );
document.write( "                x=-6+11\r\n" );
document.write( "                x=5 \r\n" );
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document.write( " Edwin

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