document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009655>Question 1009655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x-3y=16 where x=3y+11  Have tried 2x-3y+3y+11=16   2x+11-11=16-11  2x=5 but answer cannot be fraction what am I doing wrong here should I solve the problem 2x-3y=16 first then answer would be = -3\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625123 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-3y=16 where x=3y+11, so let's substitute in the equation:<BR>\n" );
document.write( "2(3y+11)-3y= 16<BR>\n" );
document.write( "6y+22-3y= 16 Simplify y on left and subtract 22 from both sides:<BR>\n" );
document.write( "3y= -6 Divide both sides by 3<BR>\n" );
document.write( "y= -2 Let's plug it in the equation and find x:<BR>\n" );
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document.write( "2x-3(-2)= 16<BR>\n" );
document.write( "2x+6= 16<BR>\n" );
document.write( "2x= 10<BR>\n" );
document.write( "x= 5<BR>\n" );
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document.write( "So there you have it:<BR>\n" );
document.write( "y= -2<BR>\n" );
document.write( "x= 5 </SPAN>\n" );
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