document.write( "Question 1009626: a women bought 7 ears of corn and 6 oranges for $2.44. a second women bought 10 ears of corn and 3 oranges for $2.26. find the price of an ear of corn and the price of an orange. \n" ); document.write( "

Algebra.Com's Answer #625093 by addingup(3677) $\"\"$ $\"About$

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7c+6o= 2.44
\n" ); document.write( "10c+3o= 2.26
\n" ); document.write( "In the second equation multiply both sides times 2:
\n" ); document.write( "20c+6o= 4.52 Now subtract this equation from the first:
\n" ); document.write( "-------------------------------------
\n" ); document.write( "7c+6o= 2.44
\n" ); document.write( "-
\n" ); document.write( "20c+6o= 4.52
\n" ); document.write( "-------------
\n" ); document.write( "-13c= -2.08 Now divide both sides by -13:
\n" ); document.write( "c= 0.16 is the cost of an ear of corn. Now in the first equation let's use this value for c:
\n" ); document.write( "7(0.16)+6o= 2.44
\n" ); document.write( "1.12+6o= 2.44 subtract 1.12 on both sides:
\n" ); document.write( "6o= 1.32 Divide both sides by 6:
\n" ); document.write( "o= 0.22
\n" ); document.write( "-----------------------------------
\n" ); document.write( "Check. We just used the first equation to find o, now let's check to see if our answer makes the second equality true:
\n" ); document.write( "10c+3o= 2.26
\n" ); document.write( "10(0.16)+3(0.22)= 2.26
\n" ); document.write( "1.6+0.66= 2.26
\n" ); document.write( "2.26 = 2.26 We've got the correct answer \n" ); document.write( "

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