document.write( "Question 1009602: The perimeter of a rectangle is 32 feet find the dimensions if the length is 4 feet longer than three times the width then find the area of the rectangle \n" ); document.write( "
Algebra.Com's Answer #625075 by tiffany222(56)\"\" \"About 
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Let width be x
\n" ); document.write( "Let length be y \r
\n" ); document.write( "\n" ); document.write( "y = 3x + 4\r
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\n" ); document.write( "\n" ); document.write( "P = (2 * width) + (2 * length)
\n" ); document.write( "P = 2x + 2y
\n" ); document.write( "32 = 2x + 2(3x + 4)
\n" ); document.write( "32 = 2x + 6x +8
\n" ); document.write( "32 = 8x + 8
\n" ); document.write( "24 = 8x
\n" ); document.write( "x = 3
\n" ); document.write( "y = 3x + 4
\n" ); document.write( " = 3 (3) + 4
\n" ); document.write( " = 9 + 4
\n" ); document.write( " = 13
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "A = width * length
\n" ); document.write( "A = x * y
\n" ); document.write( "A = 3 *13
\n" ); document.write( "A = 39\r
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\n" ); document.write( "\n" ); document.write( "Final Answer:
\n" ); document.write( "Area = 39 ft^2
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