document.write( "Question 1009518: Half life/ decay question? Thank you!\r
\n" ); document.write( "\n" ); document.write( "I happen to have 10 pounds of the most radioactive material on Earth buried in my backyard. The half life of the material is 2345 years.\r
\n" ); document.write( "\n" ); document.write( "a.) How long will it take for 5 pounds of the material to decay?
\n" ); document.write( "b.) How long will it take for there to be 2 pounds remaining?
\n" ); document.write( "c.) How much is remaining after 1000 years?
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Algebra.Com's Answer #625063 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
Basic model \"y=p%2Ae%5E%28-kt%29\"'
\n" ); document.write( "y, amount after time t
\n" ); document.write( "p, initial amount for t=0
\n" ); document.write( "k, the decay constant
\n" ); document.write( "t, time passage\r
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\n" ); document.write( "\n" ); document.write( "Example for the question mostly uses p=10.
\n" ); document.write( "(a) means, use the half-life;
\n" ); document.write( "(b) means, p=10,y=2, to find t for these.
\n" ); document.write( "(c) means, p=10, t=1000, find y.\r
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\n" ); document.write( "\n" ); document.write( "Use algebra and skills with log and exponential functions.
\n" ); document.write( "\"ln%28y%29=ln%28pe%5E%28-kt%29%29\"
\n" ); document.write( "\"ln%28y%29=ln%28p%29%2Bln%28e%5E%28-kt%29%29\"
\n" ); document.write( "\"ln%28y%29=ln%28p%29-kt%2Aln%28e%29\"
\n" ); document.write( "\"ln%28y%29=ln%28p%29-kt%2A1\"
\n" ); document.write( "\"ln%28y%29=ln%28p%29-kt\"
\n" ); document.write( "\"kt%2Bln%28y%29=ln%28p%29\"
\n" ); document.write( "\"kt=ln%28p%29-ln%28y%29\"
\n" ); document.write( "\"highlight_green%28kt=ln%28p%2Fy%29%29\"-----this equation will be used in two ways.\r
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\n" ); document.write( "\n" ); document.write( "Maybe you can do the rest of the solution on your own based on this?
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