document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1009588>Question 1009588</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jill has six times as many dimes as Joan together that have a total of 84 dimes how many dimes does Jill have \r<BR>\n" );
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document.write( "A. 7<BR>\n" );
document.write( "B. 12<BR>\n" );
document.write( "C. 63<BR>\n" );
document.write( "D. 72  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #625045 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=625045\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem says:\"Jill has 6*Joan, and it says that together, this is 6*Joan+Joan= 84. So let's call the dimes x:<BR>\n" );
document.write( "6x+x= 84 Add x on left:<BR>\n" );
document.write( "7x= 84 Now divide both sides by 7:<BR>\n" );
document.write( "x= 12 Joan has 12 dimes, and Jill has:<BR>\n" );
document.write( "12*6= 72<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "Joan has 12 and Jill has 72:<BR>\n" );
document.write( "12+72= 84, we have the correct answer. </SPAN>\n" );
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